尽管只需要执行一部分代码，但执行所有行的代码

Question

So it goes like this, When I enter a query it is parsed and two values and pulled out this is the date and indicator and gets the appropriate response to for that date initially

response = {'l_result': [{'deaths': 5, 'tested': 5,}]}

if value('DATE'):
     print("===================")
     print("this is the response ")
     print(response)
     print("===================")

if value('indicator'):
mapped_indicator = values('indicator')[-1]
   if mapped_indicator == 'Tested':
      tested_list = [
       {'total_tested': response.get('tested'),
        'new_tests': response.get('new_tests')}]
          print(tested_list)

My problem is that all the code runs. I want that if only a date is found then all information in response will be shown and if a date and indicator are found then only specific information for the indicator is shown.

my output is

===================
this is the response
{'l_result': [{'deaths': 5, 'tested': 5,}]}
===================

tested: 5

as you see the result for the entire code is there and what I wanted was just

tested: 5

Can you tell me how to do this

Answer 1

just gave you a simple example, hope this helps in your case, this is not with a dictionary structure

date = '10/19/2020'
indicator = 'Y'

if  indicator =='Y' and date == '10/19/2020':
    print('Indicator is ',indicator)
elif date == '10/19/2020':
    print('Only date has a value')


print('2nd case when indicator is empty')

date = '10/19/2020'
indicator = None

if  indicator =='Y' and date == '10/19/2020':
    print('Indicator is ',indicator)
elif date == '10/19/2020':
    print('Only date has a value') 

Answer 2

from what information you have provided, it looks like you have to use the logical operation "and" and then have a seperate for

if value('DATE'): and value('indicator')

elif.....