[英]sql query for masking only 1st 5 char of value
i need your help in creating the below query for "I have a column called 'A' with 10 digits in length I also have a column called 'B'我需要您的帮助来创建以下查询:“我有一个名为‘A’的列,长度为 10 位,我还有一个名为‘B’的列
A B
1234567890 SAM
2345678912 HELLO
7364557382 MORNING
I want to mask column A and replace the first 5 digits with column B.我想屏蔽 A 列并用 B 列替换前 5 位数字。
Post masking :后屏蔽:
SAM 67890 (with 2 spaces)
HELLO78912
MORNI557382
You can use string functions:您可以使用字符串函数:
select t.*, rpad(b, 5, ' ') || substr(a, 6) res
from mytable t
If a
is a number, you can explictly cast it first:如果a
是数字,您可以先显式转换它:
select t.*, rpad(b, 5, ' ') || substr(to_char(a), 6) res
from mytable t
You can use RPAD( B, 5, ' ' ) || SUBSTR( A, -5 )
您可以使用RPAD( B, 5, ' ' ) || SUBSTR( A, -5 )
RPAD( B, 5, ' ' ) || SUBSTR( A, -5 )
to get the first 5 characters of B
(right-padded with spaces if required) concatenated with the last 5 characters of A
. RPAD( B, 5, ' ' ) || SUBSTR( A, -5 )
获取B
的前 5 个字符(如果需要,右填充空格)与A
的最后 5 个字符连接。
For example:例如:
SELECT A,
B,
RPAD( B, 5, ' ' ) || SUBSTR( A, -5 ) AS masked_value
FROM table_name
With the sample data:使用示例数据:
CREATE TABLE table_name ( A, B ) AS
SELECT 1234567890, 'SAM' FROM DUAL UNION ALL
SELECT 2345678912, 'HELLO' FROM DUAL UNION ALL
SELECT 7364557382, 'MORNING' FROM DUAL
Outputs:输出:
\n A |一个 | B |乙 | MASKED_VALUE MASKED_VALUE\n---------: | ---------: | :------ | :------ | :----------- :-----------\n1234567890 | 1234567890 | SAM |山姆 | SAM 67890山姆 67890 \n2345678912 | 2345678912 | HELLO |你好 | HELLO78912你好78912 \n7364557382 | 7364557382 | MORNING |上午 | MORNI57382 MORNI57382 \n
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