如何查找日期并返回一行中最低的项目

Question

I have two worksheets. On Sheet1, column A is a date/time, column B is a float number, and column C is where I will put this formula. Sheet1 (example 2 columns): 6/1/2020 3:48 1.1117

Sheet2 has a date/time in column A sorted ascending and float values in columns B:DA. Sheet2 (example 7 columns): 06/01/2020 00:24 1.1103 1.1100 1.1096 1.1103 1.1114 1.1107

My formula criteria is:

• Find the same date/time from Sheet1!A2 in Sheet2!A:A
• Find all values in that row found in criteria 1 that are greater than Sheet1!L2
• Return the lowest value found

I thought I could do: Min(Filter(Sheet2!A2:DA5,("="A2)*(">"L2),1)) . But that did not work.

I appreciate any suggestions.

Answer 1

Please try this formula. It will work in Excel versions 2016 and up. For earlier versions you will need an array formula using MIN and IF separately. Look for guidance here .

[C2] =MINIFS(INDEX(Sheet2!$B$1:$G$8,MATCH($A2,Sheet2!$A:$A,0),0),INDEX(Sheet2!$B$1:$G$8,MATCH($A2,Sheet2!$A:$A,0),0),">"&$B2)

INDEX(Sheet2!$B$1:$G$8,MATCH($A2,Sheet2!$A:$A,0),0) specifies the row determined by the Match function. It's a sheet row. Therefore the data range must start in row 1. G8 is the last cell with data in my test range. You would do well to define Sheet2!$B$1:$G$8 as a named range.

The formula simply asks for the lowest value from that range to be returned which is larger than B2. The MINIFS function is designed to work with different columns but you only need one. That's why the range is repeated twice, once to draw the minimum from and once to contain the criteria.