在 JavaScript 中按降序对列表进行排序

Question

Sort the list record in JavaScript in desc order

var number; //here we are getting dynamic number from API

var test; //here we are getting dynamic text from API

for (var i; i <= accList.length; i++) {
  var odlist = 'you have :' + test + number + 

  dataList.push(odlist);
}

Current output:

1.you have : total 4 accounts of 10

2.you have : total 11 account accounts of 23 

3.you have : total 0 accounts of 100

4. you have : total 2 accounts of 6

Now I want to sort above list in descending order looking for output as per below:

1.you have : total 0 accounts of 100

2.you have : total 11 account accounts of 23 

3.you have : total 4 accounts of 10

4.you have : total 2 accounts of 6

Answer 1

var reversed = dataList.reverse();

Answer 2

You have to use Array.prototype.sort with a comparison function https://developer.mozilla.org/fr/docs/Web/JavaScript/Reference/Objets_globaux/Array/sort

But I'm not fully understanding your code.

 const dataList = ["1.you have : total 4 accounts of 10", "2.you have : total 11 account accounts of 23", "3.you have : total 0 accounts of 100", "4. you have : total 2 accounts of 6"] const reg = /(\\d+)$/; dataList.sort((a, b) => { const avalue = reg.exec(a)[0] const bvalue = reg.exec(b)[0] return +bvalue > +avalue }).forEach(s => document.write(s + "<br />"))

Answer 3

var tmpArr = []
for (id in dataList) {
    tmpArr.push(dataList[id].split(' ').reverse())
}
tmpArr.sort((a,b) => (a[0] > b[0] ? 1 : -1))
dataList = []
for (id in tmpArr) {
    dataList.push(tmpArr[id].reverse().join(' '))
}

But still, your approach to the problem is wrong, you should sort values before output.

Answer 4

let dataList = ["teyuwdh 10", "hsdhcksj 100", "euwfhiuweic 1"];

dataList.sort(
    function(a, b) {return b.match(/\d+$/) - a.match(/\d+$/)}
);

console.log('dataList: ' + JSON.stringify(dataList));

output: dataList: ["hsdhcksj 100","teyuwdh 10","euwfhiuweic 1"]