[英]Print column with a specific value in python
I am using Colab.I am trying to print data form only NY,NC, SC State我正在使用 Colab。我正在尝试仅打印 NY、NC、SC 州的数据表
confirmed_cases_USA, deaths_USA = get_confirmed_deaths_tuple_df (USA_covid_data)
# selecting rows based on condition PA, IL,OH,GA ,NC
options = ['NC',"PA"]
#options = ['NC',"PA","IL","OH","GA"]
confirmed_cases_Selected = confirmed_cases_USA[confirmed_cases_USA ['State'].isin(options)]
deaths_Selected= deaths_USA [deaths_USA ['State'].isin(options)]
print(confirmed_cases_Selected.head())
print(deaths_Selected.head())
output is :输出是:
countyFIPS County Name State ... 9/19/20 9/20/20
1921 0 Statewide Unallocated NC ... 1166 1166 1166
1922 37001 Alamance County NC ... 3695 3728 3749
1923 37003 Alexander County NC ... 483 485 488
1924 37005 Alleghany County NC ... 219 220 220
1925 37007 Anson County NC ... 549 552 553
countyFIPS County Name State ... 9/19/20 9/20/20
1921 0 Statewide Unallocated NC ... 0 0
1922 37001 Alamance County NC ... 48 54 54
1923 37003 Alexander County NC ... 5 5 5
1924 37005 Alleghany County NC ... 0 0 0
1925 37007 Anson County NC ... 4 4 4
I am trying to Group the data by state first and then get the total to confirm case of the state我试图首先按州对数据进行分组,然后得到总数以确认该州的情况
I'm not sure what get_confirmed_deaths_tuple_df
does but it doesn't look like a DataFrame.我不确定get_confirmed_deaths_tuple_df
做了什么,但它看起来不像数据帧。
USA_covid_data['State'].isin(options)
should return a boolean mask containing True
and False
. USA_covid_data['State'].isin(options)
应该返回一个包含True
和False
的布尔掩码。 Return the values that satisfy the True
condition with USA_covid_data[USA_covid_data['State'].isin(options)]
使用USA_covid_data[USA_covid_data['State'].isin(options)]
返回满足True
条件的值
It should look something like this.它应该看起来像这样。
confirmed_cases_USA, deaths_USA = get_confirmed_deaths_tuple_df(USA_covid_data[USA_covid_data['State'].isin(options)])
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