编程逻辑 - 比较 3 个值 - JS

Question

I have this snippet that is is getting 3 numbers and its working distinguing them. If one of 3 numbers is diferent than the others it must return its correspondend.

An input example: 1 1 0 0 0 0 1 0 0

output must be: C * A

The approach i had was that one:

var input = require('fs').readFileSync('stdin', 'utf8')
var lines = input.split('\n')

for (let i = 0; i < lines.length; i++) {
  var round = lines[i].split(' ').map(i => parseInt(i))
  // console.log(round); [1, 1, 0]

  var A = round[0]
  var B = round[1]
  var C = round[2]

    if(A === B && A === C){
      console.log("*");
    } else if (A === B && A !== C) {
        console.log("C");
    } else if (A !== B && A === C) {
        console.log("B");
    } else if (A !== B && A !== C) {
        console.log("A");
    }
}

Answer 1

Like @Samathingamajig said:

 function _0or1(arr) { [A,B,C] = arr if (A === B && A === C) { console.log("*"); } else if (A === B) { console.log("C"); } else if (A === C) { console.log("B"); } else { console.log("A"); } } _0or1([0,0,0]) _0or1([1,0,0]) _0or1([0,1,0]) _0or1([0,0,1]) _0or1([1,1,0]) _0or1([0,1,1]) _0or1([1,0,1]) _0or1([1,1,1])

Answer 2

I'm not sure what the problem is exactly but if it is to try to minimize the code in some way one thing to notice is that we don't care whether the the values are 0 or 1 only whether the players have chosen the same or not so once we have the values of A, B and C for a round we can just do:

(UPDATE: thanks to a comment from @Samathingamajig a redundant != comparison has been removed)

 console.log( ((A==B)&&(B==C)) ? '*' : (A==B) ? 'C' : (A==C) ? 'B' : 'A' );