将 Python ISO 日期时间转换为 Epoch

Question

I wanted to convert the iso datetime into epoch format using python datetime library.

Below is my code, but it's not working.

from datetime import datetime
epoch = datetime(1970, 1, 1)
last_updated_at = int((datetime.strptime('2020-10-16T09:29:26.580-07:00', '%Y-%m-%dT%H:%M:%S.%f %z') - epoch).total_seconds()) 

I'm getting below error

ValueError: time data '2020-09-01T12:47:54.863-07:00' does not match format '%Y-%m-%dT%H:%M:%S.%f %z'

Answer 1

use fromisoformat and timestamp :

from datetime import datetime

last_updated_at = int(datetime.fromisoformat('2020-10-16T09:29:26.580-07:00').timestamp()) 
# last_updated_at
# 1602865766

btw. your strptime format is nearly correct, just a space too much. correct would have been '%Y-%m-%dT%H:%M:%S.%f%z' .