简体   繁体   English

如何在 ANTLR4 中发出令牌?

[英]How to emit a token in ANTLR4?

This is my grammar.g4 :这是我的grammar.g4

FOO: 'x';
BAR: 'y'
  { /* here! */ };

I want tokens BAR and FOO to be emitted when the input contains y .我希望在输入包含y时发出令牌BARFOO What should I write in the here!我应该在here!写什么here! part?部分? Please, don't suggest to rewrite the grammar, this is just a test sample, my real case is much more complex.请不要建议重写语法,这只是一个测试样本,我的真实案例要复杂得多。

Here's a quick demo:这是一个快速演示:

grammar T;

@lexer::members {
  private java.util.LinkedList<Token> tokens = new java.util.LinkedList<>();

  @Override
  public Token nextToken() {
    return tokens.isEmpty() ? super.nextToken() : tokens.poll();
  }
}

parse
 : foo bar foo EOF
 ;

foo : FOO;
bar : BAR;

FOO : 'x';
BAR : 'y' {this.tokens.offer(new CommonToken(TLexer.FOO, "x"));};

SPACES : [ \t\r\n] -> skip;

Test with:测试:

TLexer lexer = new TLexer(CharStreams.fromString("x y"));
TParser parser = new TParser(new CommonTokenStream(lexer));

System.out.println(parser.parse().toStringTree(parser));

which will print:这将打印:

(parse (foo x) (bar y) (foo x) <EOF>)

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM