[英]SQL Conditional on SELECT Subquery value
I want to apply a condition check on my select subquery.我想对我的选择子查询应用条件检查。 How can I do it optimally?
我怎样才能做到最好?
Here's the initial query:这是初始查询:
SELECT
table1.column1,
(SELECT min(table2.column1) FROM table2 WHERE table2.table1Id = table1.id) as subResult
FROM table1
WHERE table1.column2 = "something"
And I want to add the WHERE condition subResult = :parameter
.我想添加 WHERE 条件
subResult = :parameter
。 And the :parameter
is optional, meaning if :parameter
is null, include row in result.并且
:parameter
是可选的,这意味着如果:parameter
为空,则在结果中包含行。
WHERE table1.column2 = "something" AND (:parameter is null or subResult = :parameter)
But I can't reference the result of the subquery subResult
inside my WHERE condition.但是我无法在 WHERE 条件中引用子查询
subResult
的结果。
I can copy/paste the subquery into the WHERE clause, but that seems sloppy and error prone:我可以将子查询复制/粘贴到 WHERE 子句中,但这似乎很草率且容易出错:
SELECT
table1.column1,
(SELECT min(table2.column1) FROM table2 WHERE table2.table1Id = table1.id) as subResult
FROM table1
WHERE table1.column2 = "something" AND (:parameter is null or (SELECT min(table2.column1) FROM table2 WHERE table2.table1Id = table1.id) = :parameter)
If you are running Oracle 12 or higher, I would recommend a lateral join:如果您运行的是 Oracle 12 或更高版本,我会推荐横向连接:
select t1.column1, t2.min_column1
from table1 t1
outer apply (select min(t2.column1) min_column1 from table2 t2 where t2.table1id = t1.id) t2
where
t1.column2 = 'something'
and (:parameter is null or t2.min_column1 = :parameter)
In earlier versions, you can use a subquery or CTE:在早期版本中,您可以使用子查询或 CTE:
select *
from (
select t1.column1,
(select min(t2.column1) from table2 t2 where t2.table1id = t1.id) as min_column1
from table1 t1
) t
where
t1.column2 = 'something'
and (:parameter is null or t2.min_column1 = :parameter)
select *
from (SELECT
table1.column1,
(SELECT min(table2.column1) FROM table2 WHERE table2.table1Id = table1.id) as subResult
FROM table1
WHERE table1.column2 = "something"
)
where subResult = decode(:p,null , subResult ,:p)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.