以相反的方式按字符串查找正则表达式模式

Question

I have a bunch of regex patterns stored in a database and I have a string as an input. My goal is to find exact pattern that matches given string. So it is kinda opposite to what regex is usually used for. Currently I am taking all the patterns from DB and check them one by one if it matches received string. I was wondering whether it is possible to find match in SQL

For example:

input string:

'/user/profile/AxuI1dn/messages'

regex array in DB:

'^/user/stories/[A-Za-z0-9]{5,7}$'
'^/user/profile/[0-9]{1,5}/$'
'^/user/profile/[A-Za-z0-9]{5,7}/messages$'
'^/user/messages/([^\s]+)/$'
'^/user/profile/[0-9]{1,5}/photos/[A-Za-z0-9]{5,7}$'
...

expected result here is

'^/user/profile/[A-Za-z0-9]{5,7}/messages$'

Answer 1

You can do this by simply using string REGEXP regexcolumn . For example:

create table regexes (id int auto_increment primary key,
                      regex varchar(50))
;
insert into regexes (regex) values
    ('^/user/stories/[A-Za-z0-9]{5,7}$'),
    ('^/user/profile/[0-9]{1,5}/$'),
    ('^/user/profile/[A-Za-z0-9]{5,7}/messages$'),
    ('^/user/messages/([^\s]+)/$'),
    ('^/user/profile/[0-9]{1,5}/photos/[A-Za-z0-9]{5,7}$')
;
SELECT *
FROM regexes 
WHERE '/user/profile/AxuI1dn/messages' regexp regex

Output:

id  regex
3   ^/user/profile/[A-Za-z0-9]{5,7}/messages$

Demo on dbfiddle