[英]Replacing multiple characters in a capturing group
I need to replace the square brackets for curly brackets and the underscores for spaces.我需要替换大括号的方括号和空格的下划线。
Input: [something_id='123'_more-info='321']
输入:
[something_id='123'_more-info='321']
Output so far: {something_id='123'_more-info='321'}
Output 到目前为止:
{something_id='123'_more-info='321'}
Required Output: {something id='123' more-info='321'}
需要 Output:
{something id='123' more-info='321'}
I can replace the brackets but I don't know where to start with searching within the capturing group to replace the spaces.我可以替换括号,但我不知道从哪里开始在捕获组中搜索以替换空格。 I'm not even sure what terms I should be searching the web for to try to find the answer.
我什至不确定我应该在 web 中搜索哪些术语来尝试找到答案。
search = re.compile(r"\[(something.*)\]")
return search.sub(r"{\1}", text_source)
If you have these texts inside longer texts, use a callable as the replacement argument to re.sub
:如果您在较长的文本中包含这些文本,请使用可调用对象作为
re.sub
的替换参数:
import re
text_source = '''Text [something_id='123'_more-info='321'] Text...'''
search = re.compile(r"\[(something[^]]*)]")
print( search.sub(lambda x: f"{{{x.group(1).replace('_', ' ')}}}", text_source) )
# => Text {something id='123' more-info='321'} Text...
See the Python demo .请参阅Python 演示。
Details细节
\[(something[^]]*)]
matches [
, then captures something
and then zero or more chars other than ]
into Group 1 and then matches ]
\[(something[^]]*)]
匹配[
,然后捕获something
,然后将]
以外的零个或多个字符放入第 1 组,然后匹配]
lambda x: f"{{{x.group(1).replace('_', ' ')}}}"
- the match is passed to the lambda where Group 1 text is enclosed with curly braces and the underscores are replaced with spaces lambda x: f"{{{x.group(1).replace('_', ' ')}}}"
- 匹配传递给 lambda,其中第 1 组文本用大括号括起来,下划线被替换有空格 If the strings are standalone strings, all you need is如果字符串是独立字符串,则您只需要
text_source = f"{{{text_source.strip('[]').replace('_', ' ')}}}"
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