将参数传递给我的 java AWS Lambda 函数

Question

Just started with using AWS Lambda's. I'm writing my functions in Java. I'd like to know if you can pass parameters to an AWS Lambda through the API Gateway? My lambda function basically makes a call to a webservice which returns JSON, create's POJO's from the JSON and then a CSV file which I upload to S3. Now this webservice you could pass productId if you wanted to, if you don't it just returns all products.

This would return the product with id of 123456 www.likssmark.com/test/api/getOrders?productId=123456

This would return all orders as JSON payload: www.likssmark.com/test/api/getOrders

How do I pass productId into my java lambda? The lambda is triggered via cloud watch on a schedule - I've been testing it using Postman.

Hope this makes sense?

Many thanks for any advice.

Answer 1

There are multiple ways to integrate lambda within an API gateway. For starters I would create a simple HTTP API with either a default route or a specific route. Attach a lambda integration to the route.

This should proxy the http request to your lambda function. You lambda handler will receive an event which contains information about the request as path, cookies, ... and also your query parameters. See the documentation for details on the passes json ( https://docs.aws.amazon.com/apigateway/latest/developerguide/http-api-develop-integrations-lambda.html ).

To determine who is actually calling the function (cloudwatch, api gateway) just test the content of the event for some fields before parsing/reading it to make sure you respond appropriate.

Answer 2

If you only need to use Cloudwatch, just pass a JSON string to your Lambda:

In your Lambda you can then pull out the data:

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;

...

public class ProductIdLambda implements RequestStreamHandler {

    public void handleRequest(InputStream inputStream, OutputStream outputStream, Context context) throws IOException {
        LambdaLogger logger = context.getLogger();

        ObjectMapper objectMapper = new ObjectMapper();
        JsonNode rootNode = objectMapper.readTree(inputStream);

        String productId = rootNode.path("productId").asInt();

This pulls the productId out of the InputStream.

If you need both CloudWatch events and API Gateway integration you can either have two different Lambda's or, to the suggestion @f7o made, introspect the incoming stream for an API Gateway call. You could have something like:

String httpMethod = rootNode.path("httpMethod").asText();
if( httpMethod != null )  // then we were called by API Gateway

The input from API Gateway will include an optional parameter in the input JSON:

"queryStringParameters": {
    "productId": "12345"
},

that you can then get your productId from.

Answer 3

You can use AWS API-Gateway to pass parameters to your AWS lambda service.
This AWS documentation describes it:
https://docs.aws.amazon.com/apigateway/latest/developerguide/api-gateway-create-api-as-simple-proxy-for-lambda.html

In my German blog I wrote an article about how to implement an AWS lambda service with Java and Spring Boot. Here I am also passing parameters over API Gateway to AWS lambda service:
https://agile-coding.blogspot.com/2020/09/aws-lambda-services-mit-spring-boot.html