我正在尝试使用 regex_replace 命令提取子字符串。 我想在这里提取“SWIFTInward”

Question

I tried below code in Ansible

---
- hosts: windows
  strategy: linear

  vars:
    war_file_path: F:\\Install\\IIBProjects\\DE\\WAR\\DE_SWIFTInward-202010.0.0.war

  tasks:
    - name: Get properties folder path for windows
      set_fact:
        endpointDetails: "{{ item | win_basename | regex_replace('\\\\(?:(?!\\\\).)*$', '') }}"
      with_items:
        - "{{ war_file_path }}"
      register: war_file_name
      when: ansible_os_family == "Windows"

Expect output : SWIFTInward
Error output which i am getting : DE_SWIFTInward-202010.0.0.war

Answer 1

The win_basename returns the file name without the directory details. So, your regex does not match it as it requires a \\ at the start.

You need

endpointDetails: "{{ item | win_basename | regex_replace('^[^_]*_([^_-]+).*', '\\1') }}"

See the regex demo

Or, use regex_search with a simple _([^_-]+)- regex :

endpointDetails: "{{ item | win_basename | regex_search('(?<=_)[^_-]+') }}"

Details

• ^[^_]*_([^_-]+).* :
  • ^ - start of a string
  • [^_]* - zero or more chars other than _
  • _ - a _ char
  • ([^_-]+) - Group 1 ( \\1 ): one or more chars other than _ and -
  • .* - the rest of the string.
• (?<=_)[^_-]+ :
  • (?<=_) - a location in string that is immediately preceded with _
  • [^_-]+ - one or more chars other than _ and - .