如何通过单击按钮运行 .exe 文件？

Question

i want to use auth system for my app. i found auth.gg . after login I want to run my app with button click. i found this.

    // string str = @"C:\windows\system32\notepad.exe";

   // string str  = @"C:\windows\system32\winamp.exe";


    string str  = @"C:\Documents and Settings\Puru\Desktop\NewsLetter\SendNewsletter.exe";
    Process process = new Process();
    process.StartInfo.FileName = str;
    process.Start();

but if i try to run on different computer location wont be same.

and i found this

System.Diagnostics.Process.Start("Application.StartupPath\\example.exe");

and i didnt understand this. Where should i locate example.exe?

after all i want to make, 1-user will run auth 2-after pass auth system will click button and second .exe file will open

Answer 1

If you're using Auth.gg, you should have a class for it where you initialize the constants and then use a function to login. This can be done from within the application, so my question to you is, why are you doing it from an external application? Best practice would be to have the login in the same executable.

If you so dearly want to do it from an external program, you could always use what you supplied.

You should then use it like so:

System.Diagnostics.Process.Start("Application.StartupPath\\example.exe"); // Folder containing your program, where example.exe is located

So you can place "example.exe" in the same folder as the application you just ran for the login. Replace "example.exe" with the name + extension of your other program that login is supposed to launch.