重载函数中枚举器的转换

Question

====================================Edited question=========================== I have read in a book that the conversion of enumerator depends to the number that the enumerator is initialized to. for EX:in this enum the first enum must convert to int and the second one must convert to double ( because the second one initialized with a number out of range of int.)

enum name{A= INT_MAX , B};

void foo(int a)
{
  print "int prameter";
}

void foo(double a)
{
  print "double parameter";
}

foo(B) // must print double parameter, no?

well we should see "double parameter" when we call foo(B) but we will see "int parameter" instead . why is that? what is the way of conversion in enumerator?

Answer 1

It's a type issue. int (*p)[2] is two dimensional but a[0] is one dimensional. So the two aren't compatible. This works though int* p = a[0];

Think about how many times you have to dereference (using * ) to get to the first integer. With int (*p)[2] it's twice

cout << **p; // print first integer

but with int a[2][2] and a[0] it's only once

cout << *(a[0]); // print first integer

but twice would be a compile error

cout << **(a[0]); // error