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为模板化函数使用默认参数

[英]Use default parameter for templated function

I have two functions which look very similar to me :我有两个与我非常相似的函数:

template <typename Predicate>
vector<int> FindTopItems(const string& query,
                         const Predicate& predicate) const;
                         
vector<int> FindTopItems(const string& query,
                         ItemStatus status = ItemStatus::Initial) const;

It is possible to use only templated version of this function?可以只使用这个函数的模板版本吗? How to set it's predicate to default value, set by enum class?如何将它的谓词设置为默认值,由枚举类设置?

So I want the following code to be compilable :所以我希望以下代码是可编译的:

int main() {

   FindTopItems(""s, [](){}); /* predicate version */
   FindTopItems(""s); /* default parameter as enum class should be used */
   
   return 0;
}

You can set the default value for predicate to ItemStatus , then make a helper class that returns your default value.您可以将 predicate 的默认值设置为ItemStatus ,然后创建一个返回默认值的辅助类。

#include <iostream>
#include <vector>
#include <string>

enum class ItemStatus {
    Initial
};

template <typename T>
auto defaultValue() {
    return T{};
}

template <>
auto defaultValue<ItemStatus>() {
    return ItemStatus::Initial;
}

template <typename Predicate = ItemStatus>
std::vector<int> FindTopItems(const std::string& query, const Predicate& predicate = defaultValue<Predicate>()) {
    if constexpr (std::is_same_v<Predicate, ItemStatus>) {
        std::cout << "ItemStatus " << static_cast<int>(predicate) << '\n';
    } else {
        std::cout << "Predicate " << predicate() << '\n';
    }
    return {};
}

int main() {
   FindTopItems(std::string{}, [](){ return 1; }); /* predicate version */
   FindTopItems(std::string{}); /* default parameter as enum class should be used */
   
   return 0;
}

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