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如何在 c# 中找到随机生成的 int 的最后一个值?

[英]How do I find the last value of a randomly generated int in c#?

I'm trying to find both last positions of X and Y of my player in a .NET Core console application.我试图在 .NET Core 控制台应用程序中找到我的播放器的 X 和 Y 的最后位置。

Every time I press W, A, S or D, it randomly generates positions (A and D for X values, W and S for Y values) in a map 1000px by 1000px.每次我按 W、A、S 或 D 时,它都会在 1000 像素 x 1000 像素的地图中随机生成位置(A 和 D 代表 X 值,W 和 S 代表 Y 值)。 The problem is when every time it says the last values, only Y value is correct and X is still random.问题是每次它说最后一个值时,只有 Y 值是正确的,而 X 仍然是随机的。

How do I find the last value of a randomly generated int (for both X and Y values) in c#?如何在 c# 中找到随机生成的 int (对于 X 和 Y 值)的最后一个值?

do
            {             
                targetPos = Console.ReadKey(true);

                if (targetPos.Key != ConsoleKey.Q)
                {
                    playerX = r.Next(0, 1000);
                    playerY = r.Next(0, 1000);
                }

                Console.WriteLine(" ");
                switch (targetPos.Key)
                {
                    case ConsoleKey.D:
                        playerX++;
                        Console.WriteLine("Right - Position X: {0} ", playerX);
                        Console.WriteLine();
                        break;

                    case ConsoleKey.A:
                        playerX--;
                        Console.WriteLine("Left - Position X: {0} ", playerX);
                        Console.WriteLine();
                        break;

                    case ConsoleKey.S:
                        playerY--;
                        Console.WriteLine("Down - Position Y: {0} ", playerY);
                        Console.WriteLine();
                        break;

                    case ConsoleKey.W:
                        playerY++;
                        Console.WriteLine("Up - Position Y: {0} ", playerY);
                        Console.WriteLine();
                        break;

                    case ConsoleKey.Q:
                        Console.WriteLine("\nLast Position X: {0}", playerX);
                        Console.WriteLine("\nLast Position Y: {0}", playerY);
                        Environment.Exit(0);
                        break;
                }
                Console.WriteLine(targetPos.Key.ToString());
            } while (targetPos.Key != ConsoleKey.Escape);

Because every time you press a key except Q, both x and y get random.因为每次按下 Q 以外的键时,x 和 y 都会变得随机。 I guess what you want is when press A or D random the x position, when press W or S random the y position, so the code should be:我猜你想要的是当按 A 或 D 随机 x 位置,当按 W 或 S 随机 y 位置,所以代码应该是:

switch (targetPos.Key)
{
    case ConsoleKey.D:
    case ConsoleKey.A:
        playerX = r.Next(0, 1000);
        break;
    case ConsoleKey.W:
    case ConsoleKey.S:
        playerY = r.Next(0, 1000);
        break;
}

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