简体   繁体   English

std::ostream 类的组成

[英]std::ostream Composition of Classes

We have the following situation:我们有以下情况:

In Classes A and B, we have overridden the << operator.在 A 类和 B 类中,我们覆盖了<<运算符。
Now, we have a new class C with data members of objects of A and B.现在,我们有一个新的类 C,其中包含 A 和 B 对象的数据成员。
How would we override the << operator here?我们将如何在这里覆盖<<运算符?

To be more specific, We need something like this:更具体地说,我们需要这样的东西:
cout<<objectOfC corresponds to cout<<correspondingObjectOfA<<correspondingObjectOfB cout<<objectOfC对应cout<<correspondingObjectOfA<<correspondingObjectOfB

I'm not getting how to modify the ostream& object so as to return it back.我不知道如何修改 ostream& 对象以将其返回。

ostream& operator<< (ostream& out, const C& obj){   // This is a friend function declared in C.h
    A* a = obj.AObject; // Returns the corresponding object of A
    B* b = obj.BObject; // Returns the corresponding object of B
    
    // Need to modify out somehow to 'cout' A and B respectively when cout is called on an object of C

    return out;
}

Any help would be greatly appreciated.任何帮助将不胜感激。 Thank you :)谢谢 :)

If you already have appropriate overrides for A and B , just use them.如果您已经有适当的AB覆盖,只需使用它们。

ostream& operator<< (ostream& out, const C& obj) {
    out << *obj.AObject << *obj.BObject;
    return out;
}

Because operator<< returns its ostream argument, you can further condense this:因为operator<<返回它的ostream参数,你可以进一步压缩这个:

ostream& operator<< (ostream& out, const C& obj) {
    return out << *obj.AObject << *obj.BObject;
}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM