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MongoDB 将 JSON 响应映射为字符串

[英]MongoDB map a JSON response into a string

var db = mongoose.connection;
        const FoundWarning = db.collection('warning').find({UserID: Warned.user.id, guildID: message.guild.id}).toArray(function(err, results) {
            console.log(results);
        })

I was trying to find more than one collection using MongoDB, I don't quite know how to map it and turn it into a String as there are multiple responses and not just one JSON document to use so I would have to map through them,我试图使用 MongoDB 找到多个集合,我不太知道如何映射它并将其转换为字符串,因为有多个响应,而不仅仅是一个 JSON 文档要使用,所以我必须通过它们进行映射,

Can someone explain how I can turn this Data to chunks that I can use like a string, an object or an array?有人可以解释一下如何将这些数据转换为可以像字符串、对象或数组一样使用的块吗?

I suppose I have to parse it and map it first, correct me if I'm wrong But I don't think I know how to do that我想我必须先解析它并映射它,如果我错了,请纠正我但我认为我不知道该怎么做

Here is the photo of the current result that I have这是我当前结果的照片在此处输入图片说明

I wanted to (for example) get the "Reason" part of it in a string alone and send each "Reason" along side with the "UserName" and send it as a message on discord using discord.js so like loop through them for example我想(例如)将它的“原因”部分单独放在一个字符串中,并将每个“原因”与“用户名”一起发送,并使用 discord.js 将其作为不和谐消息发送,例如循环遍历它们例子

Edit: i forgot to mention that "Warned" is编辑:我忘了提到“警告”是

let Warned = message.mentions.members.first();

Sorry if I'm not good at explaining, I would appreciate edits if you understand what's the issue that I'm facing抱歉,如果我不擅长解释,如果您了解我面临的问题,我将不胜感激

Like I said here就像我在这里说的

You can simply access the Reason property of an object.您可以简单地访问对象的Reason属性。 What you are facing is an array of objects and each object inside the array contains a Reason property.您面对的是一个对象数组,数组中的每个对象都包含一个Reason属性。 You can either access one object, for example, results[0] and then access the Reason property like this results[0].Reason or you can store all the reasons inside an array like this:您可以访问一个对象,例如, results[0]然后像这样访问Reason属性results[0].Reason或者您可以将所有原因存储在一个数组中,如下所示:

const reasons = results.map(result => result.Reason);

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