如何将产品计数到多个过滤器

Question

UPDATED

I like to make product filter module like this one Online Shop , when you click one of the filters to count current products in other filters

For example if this is frontend and their are checkboxes and their are UNchecked atm

Size (group_id)
  10m (option_id: 52) (21 products)
  20m (option_id: 51) (1 product)

Color (group_id)
   Green (option_id: 49) (22 products)
   Black (option_id: 38) (1 product)

If a user select 10m (option_id: 52) the filter counter should become like this

Size (group_id)
  10m (option_id: 52) (21 products)
  20m (option_id: 51) (1)

Color (group_id)
   Green (option_id: 49) (2)
   Black (option_id: 38) (0)

I made one table only for counting where i keep group_id,option_id,product_id,category_id,manufacturer_id

I make query that count products to filter but problem is that i cant return other filter counter (option_id: 38) in same category and manufacturer counter for all manufacturer in same category , any ideas how to make it ?

SELECT sd.*, COUNT(sd.product_id) FROM filter_counter sd WHERE sd.product_id IN (SELECT c.product_id FROM filter_counter c WHERE c.option_id IN (52) AND c.category_id = 127) AND sd.category_id = 127 GROUP BY sd.option_id

CREATE TABLE `filter_counter` (
  `id` int(11) NOT NULL,
  `group_id` int(11) NOT NULL,
  `option_id` int(11) NOT NULL,
  `product_id` int(11) NOT NULL,
  `category_id` int(11) NOT NULL,
  `manufacturer_id` int(11) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

INSERT INTO `filter_counter` (`id`, `group_id`, `option_id`, `product_id`, `category_id`, `manufacturer_id`) VALUES
(1, 33, 52, 5124, 65, 36),
(2, 33, 52, 5124, 127, 36),
(3, 33, 52, 5125, 65, 36),
(4, 33, 52, 5125, 127, 36),
(5, 33, 52, 5138, 65, 36),
(6, 33, 52, 5138, 127, 36),
(7, 33, 52, 5141, 65, 36),
(8, 33, 52, 5141, 127, 36),
(9, 33, 52, 5146, 65, 36),
(10, 33, 52, 5146, 127, 36),
(11, 33, 52, 5147, 65, 36),
(12, 33, 52, 5147, 127, 36),
(13, 33, 52, 5148, 65, 36),
(14, 33, 52, 5148, 127, 36),
(15, 33, 52, 5149, 65, 36),
(16, 33, 52, 5149, 127, 36),
(17, 33, 52, 5150, 65, 36),
(18, 33, 52, 5150, 127, 36),
(19, 33, 52, 5151, 65, 36),
(20, 33, 52, 5151, 127, 36),
(21, 33, 52, 5152, 65, 36),
(22, 33, 52, 5152, 127, 36),
(23, 33, 52, 5153, 65, 36),
(24, 33, 52, 5153, 127, 36),
(25, 33, 52, 5154, 65, 36),
(26, 33, 52, 5154, 127, 36),
(27, 33, 52, 5155, 65, 36),
(28, 33, 52, 5155, 127, 36),
(29, 33, 52, 5156, 65, 36),
(30, 33, 52, 5156, 127, 36),
(31, 33, 52, 5157, 65, 36),
(32, 33, 52, 5157, 127, 36),
(33, 33, 52, 7042, 65, 38),
(34, 33, 52, 7042, 127, 38),
(35, 33, 52, 7048, 65, 38),
(36, 33, 52, 7048, 127, 38),
(37, 33, 52, 7124, 65, 0),
(38, 33, 52, 7124, 127, 0),
(39, 32, 49, 7185, 65, 0),
(40, 32, 49, 7185, 127, 0),
(41, 32, 49, 7517, 65, 39),
(42, 32, 49, 7517, 127, 39),
(43, 32, 49, 7518, 65, 39),
(44, 32, 49, 7518, 127, 39),
(45, 32, 49, 7538, 65, 39),
(46, 32, 49, 7538, 127, 39),
(47, 32, 49, 7657, 65, 39),
(48, 32, 49, 7657, 127, 39),
(49, 32, 49, 7658, 65, 39),
(50, 32, 49, 7658, 127, 39),
(51, 32, 49, 7797, 65, 21),
(52, 32, 49, 7797, 127, 21),
(53, 32, 49, 7798, 65, 21),
(54, 32, 49, 7798, 127, 21),
(55, 32, 49, 7799, 65, 21),
(56, 32, 49, 7799, 127, 21),
(57, 32, 49, 7800, 65, 21),
(58, 32, 49, 7800, 127, 21),
(59, 32, 49, 7801, 65, 21),
(60, 32, 49, 7801, 127, 21),
(61, 32, 49, 7802, 65, 21),
(62, 32, 49, 7802, 127, 21),
(63, 32, 49, 7803, 65, 21),
(64, 32, 49, 7803, 127, 21),
(65, 32, 49, 7804, 65, 21),
(66, 32, 49, 7804, 127, 21),
(67, 32, 49, 7805, 65, 21),
(68, 32, 49, 7805, 127, 21),
(69, 32, 49, 7806, 65, 21),
(70, 32, 49, 7806, 127, 21),
(71, 32, 49, 7807, 65, 21),
(72, 32, 49, 7807, 127, 21),
(73, 32, 49, 7808, 65, 21),
(74, 32, 49, 7808, 127, 21),
(75, 32, 49, 7809, 65, 21),
(76, 32, 49, 7809, 127, 21),
(77, 32, 49, 7810, 65, 21),
(78, 32, 49, 7810, 127, 21),
(79, 29, 38, 7811, 65, 21),
(80, 29, 38, 7811, 127, 21),
(81, 32, 49, 8020, 65, 21),
(82, 32, 49, 8020, 127, 21),
(83, 33, 52, 8020, 65, 21),
(84, 33, 52, 8020, 127, 21),
(85, 32, 49, 8021, 65, 21),
(86, 32, 49, 8021, 127, 21),
(87, 33, 51, 8021, 65, 21),
(88, 33, 51, 8021, 127, 21),
(89, 33, 52, 8021, 65, 21),
(90, 33, 52, 8021, 127, 21);

My database and query example

Answer 1

For example if this is frontend and their are checkboxes and their are UNchecked atm

 Size (group_id) 10m (option_id: 52) (21 products) 20m (option_id: 51) (1 product) Color (group_id) Green (option_id: 49) (22 products) Black (option_id: 38) (1 product)

SELECT COUNT(DISTINCT CASE WHEN option_id = 52 THEN product_id END) p52,
       COUNT(DISTINCT CASE WHEN option_id = 51 THEN product_id END) p51,
       COUNT(DISTINCT CASE WHEN option_id = 49 THEN product_id END) p49,
       COUNT(DISTINCT CASE WHEN option_id = 38 THEN product_id END) p38
FROM filter_counter;

If a user select 10m (option_id: 52) the filter counter should become like this

Size (group_id) 10m (option_id: 52) (21 products) 20m (option_id: 51) (1) Color (group_id) Green (option_id: 49) (2) Black (option_id: 38) (0)

SELECT COUNT(DISTINCT CASE WHEN option_id = 52 THEN product_id END) p52,
       COUNT(DISTINCT CASE WHEN option_id = 51 THEN product_id END) p51,
       COUNT(DISTINCT CASE WHEN option_id = 49 THEN product_id END) p49,
       COUNT(DISTINCT CASE WHEN option_id = 38 THEN product_id END) p38
FROM filter_counter
JOIN ( SELECT DISTINCT product_id
       FROM filter_counter
       WHERE option_id IN (52) ) filter1 USING (product_id);

fiddle

If user checks additional filter in the same group then the next value is added into the condition. For example, if he checks option_id = 51 which is in the same group with option_id = 52 then filtering subquery become

JOIN ( SELECT DISTINCT product_id
       FROM filter_counter
       WHERE option_id IN (52, 51) ) filter1 USING (product_id)

If user checks additional filter in another group then additional filterX subquery added. For example, if he checks option_id = 49 then the next subquery added to the query:

JOIN ( SELECT DISTINCT product_id
       FROM filter_counter
       WHERE option_id IN (49) ) filter2 USING (product_id)

---

is there any way output to become one per line ?

SELECT options.option_id,
       COUNT(DISTINCT CASE WHEN filter_counter.option_id = options.option_id 
                           THEN product_id 
                           END) option_count
FROM filter_counter
CROSS JOIN ( SELECT DISTINCT option_id
             FROM filter_counter ) options
JOIN ( SELECT DISTINCT product_id
       FROM filter_counter
       WHERE option_id IN (52) ) filter1 USING (product_id)
GROUP BY options.option_id;

fiddle

Answer 2

Sadly I cannot make a lot of sense out of your example:

for example if i have one product_id 8020 with two options ( options_id 49 and 52 ) when user select option 49 count must show 1 product in option 49 and 1 product in option 52

But following your title, ONE TO MANY and your problem:

But the problem is coming when you have to select one or more filters how to count how many products are sill enable to combinate between filters ?

I will try to explain with a generalised answer.

First you have to figure out what makes a product able to fit in the two filters you have selected. If you SELECT filter_id '1' and '5'

(1, 32, 49, 8020, 65, 21)

(5, 32, 49, 8021, 65, 21)

We can see that the only thing they differ in is the product_id so if you want to select all products who share everything except their product_id you can do a very basic SELECT product_id, COUNT(product_id) AS total FROM filter_counter WHERE group_id = 32 AND category_id = 65

But if you want to make the entire solution based on a ONE TO MANY as mentioned in your title I would suggest you create a new table for your products and make every product have a filter id instead. Then you can count the amount of products who share the same filter. You can read more about it in this stackoverflow question: How to implement one-to-one, one-to-many and many-to-many relationships while designing tables?

Example:

CREATE TABLE 'product' (
   product_id PRIMARY KEY,
   filter_id int REFERENCES filter_counter(id),
   ... More info for product
)