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在 AWS Aurora/postgres 上收听/通知

[英]LISTEN/NOTIFY on AWS Aurora/postgres

原文 2020-11-03 22:31:08 3 1 postgresql/ amazon-rds/ amazon-aurora/ pg-notify

I am hoping to implement a trigger that fires a notify on table change in PostgreSQL, but I am unable to find any definite answer to if it would work in a cluster.我希望实现一个触发器，在 PostgreSQL 中的表更改时触发通知，但我无法找到它是否可以在集群中工作的任何明确答案。

Does PostgreSQL listen/notify work on AWS Aurora (both provisioned and serverless), and can I expect all clients to receive notifications regardless of what instance they are connected to? PostgreSQL 侦听/通知是否在 AWS Aurora（预配置和无服务器）上工作，我是否可以期望所有客户端都收到通知，而不管它们连接到哪个实例？

If yes, are there any major performance concerns?如果是，是否有任何重大的性能问题？

Thanks :)谢谢：）

1 个解决方案

The best AWS Documentation implies - YES, it does work最好的 AWS 文档暗示 - 是的，它确实有效

Specifically for Aurora Serverless, there is an advisory that "LISTEN/NOTIFY" is NOT RECOMMENDED.特别是对于 Aurora Serverless，有一个不推荐“聆听/通知”的建议。 This implies that it's possible with Aurora Serverless but not advisable.这意味着 Aurora Serverless 是可能的，但不可取。 It also implies that normal RDS LISTEN/NOTIFY does work and is ok to use.这也意味着正常的 RDS LISTEN/NOTIFY 确实有效并且可以使用。

https://docs.aws.amazon.com/AmazonRDS/latest/AuroraUserGuide/aurora-serverless.html https://docs.aws.amazon.com/AmazonRDS/latest/AuroraUserGuide/aurora-serverless.html

Currently, certain SQL queries and commands, such as cursors with hold (DECLARE name ... CURSOR WITH HOLD FOR query);当前，某些 SQL 查询和命令，例如带有保留的游标（DECLARE name ... CURSOR WITH HOLD FOR 查询）； session-level advisory locks;会话级咨询锁； temporary relations;临时关系； and asynchronous notifications (LISTEN, NOTIFY commands) prevent scaling and are not recommended和异步通知（LISTEN、NOTIFY 命令）会阻止缩放，不推荐使用

My own quick test on AWS shows - Yes, it does work我自己在 AWS 上的快速测试显示 - 是的，它确实有效

Launch Instance with Public Access使用公共访问启动实例

... ...

Allow Traffic允许流量

Run command in dbeaver在 dbeaver 中运行命令

Note: This test doesn't show a successful receipt of a notification.注意：此测试未显示成功收到通知。 That will need a quick console application to test that.这将需要一个快速的控制台应用程序来测试。