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使用中断减慢程序（在 c 和汇编中）

[英]Slowing down a program (in c and assembly) using interrupts

原文 2020-11-04 11:51:50 3 1 c/ assembly/ interrupt/ x86-16/ dosbox

I want to slow down a program using interrupts according to these conditions :我想根据这些条件使用中断减慢程序的速度：

if I press the up arrrow on the keyboard the speed will increase如果我按键盘上的向上箭头，速度会增加
if I press the down arrow on the keyboard the speed will decrease如果我按下键盘上的向下箭头，速度会降低

I want to do it by using interrupts : if the speed should decrease I will mask more interrupts and if the speed should increase I will unmask interrupts.我想通过使用中断来做到这一点：如果速度应该降低，我将屏蔽更多的中断，如果速度应该增加，我将取消屏蔽中断。
I know how to reach to the keyboard interrupt and to mask and unmask interrupts.我知道如何到达键盘中断并屏蔽和取消屏蔽中断。
I just don't know how to reach the program speed.我只是不知道如何达到程序速度。 I am writing the code in c and assembly.我正在用 c 和汇编编写代码。

1 个解决方案

One thing you can do is to intercept one of the interrupts such as the BIOS clock tick int 08h or (better) MS-DOS int 1Ch handler called at about 18 hertz.您可以做的一件事是拦截中断之一，例如以大约 18 赫兹调用的 BIOS 时钟滴答int 08h或（更好的）MS-DOS int 1Ch处理程序。 Then add time-wasting loops based on a variable that is controlled by certain keyboard events.然后根据由某些键盘事件控制的变量添加浪费时间的循环。

Make sure you re-enable interrupts before each delay.确保在每次延迟之前重新启用中断。

At the end of the program you are responsible for restoring the original interrupt vector.在程序结束时，您负责恢复原始中断向量。

You can't speed a program up faster than its starting speed without adjusting the emulation.在不调整仿真的情况下，您无法将程序加速到比其启动速度更快的速度。