从python中的两个字符串中一一删除字母

Question

a = "ccdd"

b = "ccddcc"

I want to print:

a = " "

b = 'cc'

By removing 'c' from both strings until no more 'c' left in any one of the string.

Then remove 'd' as 'c' was removed

Answer 1

When you know exactly len(a) < len(b) , you can try this:

a = "ccdd"
b = "ccddcc"
while a and a[0] == b[0]:
     a = a[1:]
     b = b[1:]

Or you don't know which string will end first, try this:

while (a and b) and a[0] == b[0]:
     a = a[1:]
     b = b[1:]

Here are just the code written based on what you're providing, and remove by order.

Answer 2

Try this:

a = "ccdd"

b = "ccddcc"


def f(a, b):
    myList = list(set(a) & set(b))
    status = True
    while status == True:
        status = False
        if len(myList) > 0:
            status = True
            index1 = a.find(myList[0])
            index2 = b.find(myList[0])
            a = a[:index1] + a[index1 + 1:]
            b = b[:index2] + b[index2 + 1:]
            myList = list(set(a) & set(b))
    return a, b


a, b = f(a, b)

print(a)
print(b)