[英]You try to generate GraphQL Type with name "Projects" from mongoose model but this type already exists in SchemaComposer
I use different mongodb db's to store the same mongoose schema records "Pages".我使用不同的 mongodb 数据库来存储相同的猫鼬模式记录“页面”。 Because of that i wanted to have X graphql endpoints - each should serve the "Pages" of the requested database.
因此,我希望拥有 X 个 graphql 端点 - 每个端点都应为请求的数据库的“页面”提供服务。
Example: localhost:3000/graphql/:database
示例:
localhost:3000/graphql/:database
For that reason i created a schemaComposer that gets the database name from a route (express > request.param.database)出于这个原因,我创建了一个 schemaComposer,它从路由中获取数据库名称(express > request.param.database)
import { composeMongoose } from 'graphql-compose-mongoose'
import { SchemaComposer } from 'graphql-compose'
import { Pages } from '../../mongoose/models/PagesModel.js'
import { Projects } from '../../mongoose/models/ProjectsModel.js'
const gqlSchemaComposerBuilder = (database) => {
const gqlSchemaComposer = new SchemaComposer()
const ProjectsTC = composeMongoose(Projects, {})
const PagesTC = composeMongoose(Pages(database), {})
gqlSchemaComposer.Query.addFields({
pageMany: PagesTC.mongooseResolvers.findMany(),
pageOne: PagesTC.mongooseResolvers.findOne(),
projectMany: ProjectsTC.mongooseResolvers.findMany(),
projectOne: ProjectsTC.mongooseResolvers.findOne()
})
gqlSchemaComposer.Mutation.addFields({
projectCreateOne: ProjectsTC.mongooseResolvers.createOne(),
projectUpdateOne: ProjectsTC.mongooseResolvers.updateOne(),
projectRemoveOne: ProjectsTC.mongooseResolvers.removeOne()
})
return gqlSchemaComposer.buildSchema()
}
export default gqlSchemaComposerBuilder
The Problem is, as soon as the both composeMongoose
declarations are wrapped inside the function i get this Error:问题是,只要两个
composeMongoose
声明都包含在函数中,我就会收到此错误:
{"errors":[{"message":"You try to generate GraphQL Type with name Projects from mongoose model but this type already exists in SchemaComposer. Please choose another type name \"composeWithMongoose(model, { name: 'NewTypeName' })\", or reuse existed type \"schemaComposer.getOTC('TypeName')\", or remove type from SchemaComposer before calling composeWithMongoose method \"schemaComposer.delete('TypeName')\"."}]}
By default composeMongoose()
uses the global schemaComposer
, so you need to pass your gqlSchemaComposer
in the options of componseMongo
默认情况下
composeMongoose()
使用全局schemaComposer
,因此您需要在gqlSchemaComposer
的选项中传递您的componseMongo
const gqlSchemaComposer = new SchemaComposer()
const ProjectsTC = composeMongoose(Projects, { schemaComposer: gqlSchemaComposer })
const PagesTC = composeMongoose(Pages(database), {schemaComposer: gqlSchemaComposer})
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