输入任意数字并使用while循环以降序打印所有奇数

Question

How do i print all odd number in descending order?

int a = in.nextInt();
int counter = 0;

while(counter < a){
    if ((counter % 2) != 0){
        System.out.println(counter);
    }
    counter--;
}

input: 10 Expected output: 9 7 5 3 1

Answer 1

You can create an array of numbers, then sort it. add numbers to an array instead of printing numbers. Then sort the array. Then use a foreach to print all.

Answer 2

use a for loop:

int a = in.nextInt();;
        
for(int i = a; i > 0; i--) {
    if(i % 2 != 0) {
        System.out.println(i);
    }
}

Answer 3

Use this

int a = in.nextInt();

while(a > 0){
    if ((a % 2) != 0){
        System.out.println(a);
    }
    a--;
}

Answer 4

No need you use counter

int a = 10;

    while(a!=0){
        if ((a % 2) != 0){
            System.out.println(a);
        }
        a--;
    }

Answer 5

How about:

int a = in.nextInt();
if (a % 2 == 0) a--;

while (a > 0) {
    System.out.println(a);
    a -= 2;
}