我正在尝试为用户创建一个程序来输入 5 个数字并检查它们在数组中是否连续，但我遇到了问题

Question

I think I've managed to make most of the program but ran into a problem when entering the numbers at the input stage to later be sorted. Could someone help me to understand what I need to fix at the input stage or how I need to declare my variables in order for them to be sorted in the array later on in the program?

This is the code:

import java.util.*;

public class Main{
    int a;
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.print("Please enter your numbers to be sorted in the array: ");
        a = sc.nextInt();
        int b = sc.nextInt();
        int c = sc.nextInt();
        int d = sc.nextInt();
        int e = sc.nextInt();    
    }

    public static boolean checkConsecutive(int[] A)   {
        int min = Integer.MAX_VALUE, max = Integer.MIN_VALUE;

        // to find the largest and smallest numbers in the array
        for (int i: A) {
            if (i < min) { min = i; }
            if (i > max) { max = i; }
        }

        // in order for an array to contain consecutive integers, the difference
        // between maximum and element element in it should be exactly n-1
        if (max - min != A.length - 1) {
            return false;
        }

        // create an empty set (we can also use a visited array)
        Set<Integer> visited = new HashSet<>();

        // traverse the array and checks if each element appears only once
        for (int i: A)
        {
            // if element is seen before, return false
            if (visited.contains(i)) {
                return false;
            }

            // mark element as seen
            visited.add(i);
        }

        // we reach here when all elements in the array are distinct
        return true;
    }

    // Check if an array is formed by consecutive integers
    public static void printInfo(String[] args)    { 
        int[] A = { a, b, c, d, e};

        if (checkConsecutive(A)) {
            System.out.print("Array contains consecutive integers");
        } else {
            System.out.print("Array do not contain consecutive integers");
        }
    }
}

Answer 1

The problem you had that the variables of a, b, c, d, e should declared globally and calling the printInfo() .

Otherwise you can create the following ask for the size of the array and enter the number and check if the array contains consecutive integer or not

import java.util.*;

public class Main {

  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    System.out.print("Please enter the size of the array: ");
    int size = Integer.parseInt(sc.nextLine());
    int[] A = new int[size];
    for (int i = 0; i < size; i++) {
      A[i] = sc.nextInt();
    }

    if (checkConsecutive(A)) {
      System.out.print("Array contains consecutive integers");
    } else {
      System.out.print("Array does not contain consecutive integers");
    }
    sc.close();
  }

  public static boolean checkConsecutive(int[] A) {
    int min = Integer.MAX_VALUE, max = Integer.MIN_VALUE;

    // to find the largest and smallest numbers in the array
    for (int i : A) {
      if (i < min) {
        min = i;
      }
      if (i > max) {
        max = i;
      }
    }

    // in order for an array to contain consecutive integers, the difference
    // between maximum and element element in it should be exactly n-1
    if (max - min != A.length - 1) {
      return false;
    }

    // create an empty set (we can also use a visited array)
    Set<Integer> visited = new HashSet<>();

    // traverse the array and checks if each element appears only once
    for (int i : A) {
      // if element is seen before, return false
      if (visited.contains(i)) {
        return false;
      }

      // mark element as seen
      visited.add(i);
    }

    // we reach here when all elements in the array are distinct
    return true;
  }
}

---

, output

Please enter the size of the array: 5
1 2 3 4 5
Array contains consecutive integers
Process finished with exit code 0