将字符串拆分为字符串和数字

Question

I'm trying to split this string ( incoming_string ) to digits and string to the next view ( result ):

incoming_string = '02, 102, 702New York' # Also possible incoming strings: '06, 25Jerusalem' or '34Saint Luise'

result = {'New York': ['02', '102', '702']}

I'm found this approcach, but I think this is not a best way:

import re


digits = re.findall('\d+', incoming_string)  # ['02', '102', '702']
strings = re.findall('[a-z, A-Z]+', incoming_string)[-1]  # 'New York'

By best way I mean a most concise, understandable and pythonic way, preferable without imports. All symbols are the same encoding (ascii)

Answer 1

Use this:

(\\d{2}), (\\d{3}), (\\d{3})(.+)

Demo

Code:

import re

incoming_string = '02, 102, 702New York'
print(re.sub("(\d{2}), (\d{3}), (\d{3})(.+)", "{\\4: [\\1, \\2, \\3]}", incoming_string))

ouput:

{New York: [02, 102, 702]}

Answer 2

The trouble is finding the index where the list stops and the key value starts. We can make a function that helps us find the first "non-list character". Then it's a matter of splitting the string in two using that index, after which we can split the first part into a list using the ", " delimiter.

def get_first_non_list_char_index(incoming_string):
    for i, c in enumerate(incoming_string):
        if c not in "1234567890, ":
            return i

incoming_string = "02, 102, 702New York"
char_index = get_first_non_list_char_index(incoming_string)

result = {incoming_string[char_index:]: incoming_string[:char_index].split(", ")}

result = {'New York': ['02', '102', '702']}

Answer 3

import less solution as requested:

incoming_string = '02, 102, 702New York'
letters = ''.join(i for i in incoming_string if i.isalpha() or i.isspace())
numbers = ''.join(i for i in incoming_string if i.isdigit() or i.isspace())
result = {letters.strip(): numbers.split()}
print(result)

Output:

{'New York': ['02', '102', '702']}

Answer 4

You can use re.split to get this result:

sl=['02, 102, 702New York',  
'06, 25Jerusalem',
'34Saint Luise']

import re

for s in sl:
    fields=re.split(r'(?<=\d)(?=[a-zA-Z])', s, maxsplit=1)
    print(s, "=>", {fields[1]:re.split(r',[ ]*',fields[0])})

Prints:

02, 102, 702New York => {'New York': ['02', '102', '702']}
06, 25Jerusalem => {'Jerusalem': ['06', '25']}
34Saint Luise => {'Saint Luise': ['34']}