如何在C++中将十六进制值转换为整数？

Question

I am having the hexadecimal value in unsigned char and i am not finding any way to change this hexadecimal value as integer. Please assist on this.

unsigned char c = '0x01';
int convertasint = (int)c;//not working
int convertasint1 = (atoi)c;//not working

Please guide me how to achieve this.

Answer 1

unsigned char variables are integers already (so are char ). You don't have to do anything special to convert them. This code works

unsigned char c = 0x01;       // assign integer to unsigned char
int convertasint = c;         // now assign to int
cout << convertasint << '\n'; // this prints 1

Also please note that hexadecimal integers are just integers, just like decimal integers. You also don't need to convert between them.