Python 遍历列表以获取字典值
[英]Python iterate through list to get dictionary values
问题描述
I have this list object that i would like to recursively iterate until i find "nodes" that have "hostname" value and count states by it's code.
我有这个列表对象，我想递归迭代，直到找到具有“主机名”值的“节点”并通过它的代码计算状态。 The problem is i can have multiple "nodes" inside each other randomly.问题是我可以在彼此内部随机拥有多个“节点”。
Disclaimer: I'm no developer, just an enthusiast so go easy on me!免责声明：我不是开发人员，只是一个爱好者，所以放轻松！ :) :)
I've already tried bunch of loops (for, while and so on) calling some functions to validate the content of nodes, but it keeps me failing when i have multiple nodes inside each other.我已经尝试了一堆循环（for、while 等等）调用一些函数来验证节点的内容，但是当我有多个节点时，它让我失败。
Any help would be appreciated, Cheers,任何帮助将不胜感激，干杯，
[
u"MY CONTAINER",
u"MY APP",
"0",
"",
{
"title": u"MyApp",
"state": 0,
"nodes": [
{
"title": u"AppStuff01",
"state": 0,
"nodes": [
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
],
"currently_active": True,
},
{
"title": u"AppStuff02",
"state": 0,
"nodes": [
{
"title": u"MySubApp",
"state": 0,
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
"nodes": [
{
"title": u"Another Random Node",
"state": 0
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
},
],
],
"currently_active": True,
}
],
"currently_active": True,
},
],
"currently_active": True,
},
"0",
"0",
]
1 个解决方案
解决方案1
1 已采纳 2020-11-09 15:54:00
You can recursively check through your list to find nodes with hostname property:您可以递归检查您的列表以查找具有hostname属性的nodes ：
(PS: your original list had some syntax errors that I had to fix) （PS：你的原始列表有一些语法错误，我必须修复）
If your list is a variable like this:如果您的列表是这样的变量：
my_list = [
u"MY CONTAINER",
u"MY APP",
"0",
"",
{
"title": u"MyApp",
"state": 0,
"nodes": [
{
"title": u"AppStuff01",
"state": 0,
"nodes": [
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
{
"title": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"CPU ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Memory ",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
"currently_active": True,
},
],
"currently_active": True,
},
{
"title": u"AppStuff02",
"state": 0,
"nodes": [
{
"title": u"MySubApp",
"state": 0,
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
"nodes": [
{
"title": u"Another Random Node",
"state": 0,
"nodes": [
{
"title": u"Service Y",
"hostname": u"HOSTX",
"state": 0,
},
],
},
],
},
],
"currently_active": True,
}
],
"currently_active": True,
},
],
"currently_active": True,
},
"0",
"0",
]
Then you can use a function like this:然后你可以使用这样的函数：
def find_nodes(to_check):
nodes = []
if type(to_check).__name__ != "list":
return nodes
for element in to_check:
if type(element).__name__ == "dict":
if "hostname" in element:
nodes.append(element)
if "nodes" in element:
nodes.extend(find_nodes(element["nodes"]))
return nodes
print(find_nodes(my_list))
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.