如何在使用 Makefile 运行程序时添加命令行参数？

Question

I have the following Main class in java where I pass arguments from the command-line:

public class Main {
    public static void main (String [] args) {
        Conversion c = new Conversion();
        c.convertHPP(args[0], args[1]);
        c.convertCPP(args[0], args[1]);
    }
}

I have a Makefile and with the option make run-java I run the program:

JFLAGS = -g
JC = javac

.SUFFIXES: .java .class

.java.class:
    $(JC) $(JFLAGS) $*.java

CLASSES = \
          Main.java \
          Conversion.java \
          Book.java

make-java: classes

classes: $(CLASSES:.java=.class)

run-java:
    java Main
    
clean:
    $(RM) *.class 

What I want to do is to pass the command-line arguments (argv) which are the name of the files to convert, from the makefile to the main. I want to do something like this in the terminal:

make java-run arg1 arg2

How can I change my Makefile so that the run-java: can allow me to pass arguments and to send it to the main?

Thanks !

Answer 1

Use a variable:

make run-java ARGS="arg1 arg2"

And then in the makefile:

run-java
    java Main $(ARGS)