删除熊猫数据框中带有零的行

Question

I want to delete rows were on of the column values is equal to Zero. What I allready tried:

Method 1:

df =pd.read_csv('Test.txt', sep="\t", skiprows=10,header=None, 
                                names=["Gewicht", "Temperaturlinks", 
                                "Temperaturrechts",'Raumtemperatur'])
df =df[df['Gewicht'] !=0]
df

Method 2:

# Get names of indexes for which column Stock has value No
indexNamesL = IgnoriereAnfangswerte[IgnoriereAnfangswerte["Gewicht"]== 0 ].index
# Delete these row indexes from dataFrame
IgnoriereNullL=IgnoriereAnfangswerte.drop(indexNamesL,inplace=True)
            print(IgnoriereNull)

Method 3:

IgnoriereAnfangswerte == 0
TabelleNull= IgnoriereAnfangswerte[~(IgnoriereAnfangswerte == 0).any(axis=1)]
TabelleNull

´´´ My Dataframe looks like this:

Gewicht     a           b           c  

0 24,534000 217,140000 219,970000 27,300000

1 0,000000 217,350000 220,110000 27,300000

Answer 1

your method 1 looks OK. also try:

df = df.drop(df[df['Gewicht']==0].index)

Answer 2

A part of your problem is that it seems that you have pairs of numbers in each column. In Python, these are tuples .

Here is a way to create the dataframe in Python:

import pandas as pd
rows = [[(24,534000), (217,140000), (219,970000), (27,300000)], 
        [(0,0), (217,350000), (220,110000), (27,300000)]]

df =pd.DataFrame(data=rows, columns=["Gewicht", "Temperaturlinks", "Temperaturrechts",'Raumtemperatur'])

This prints out:

        Gewicht Temperaturlinks Temperaturrechts Raumtemperatur
0  (24, 534000)   (217, 140000)    (219, 970000)   (27, 300000)
1        (0, 0)   (217, 350000)    (220, 110000)   (27, 300000)

In Pandas, you drop a row meeting a certain criterion. Here is how you can drop a row with a Gewicht of (0, 0) :

df[df['Gewicht'] != (0,0) ]

This will print out:

        Gewicht Temperaturlinks Temperaturrechts Raumtemperatur
0  (24, 534000)   (217, 140000)    (219, 970000)   (27, 300000)