[英]Mongoose method findOne takes too long and returns sometimes undefined
Im calling findOne to find a user and then Im saving his commands into my variable commands, which I return and it is sometimes undefined.我调用 findOne 来找到一个用户,然后我将他的命令保存到我的变量命令中,我返回它有时是未定义的。
const findAllCommands = async (user) => {
const commands = [];
const cache = await checkCache(user);
if (cache) {
logger.info('Existing CACHE found!');
return cache;
}
await User.findOne({ username: user }, (err, res) => {
if (err) {
logger.error('ERROR: ' + err);
throw new Error(err);
}
res.commands.forEach((v) => {
commands.push(v);})
});
await addToCache(user, JSON.stringify(commands));
return commands;
};
I use a try catch
block whenever I use async await
syntax.每当我使用async await
语法时,我都会使用try catch
块。 Also if you need only one field you can query only for that field.此外,如果您只需要一个字段,则只能查询该字段。
const findAllCommands = async (user) => {
try {
const cache = await checkCache(user);
if (cache) {
logger.info('Existing CACHE found!');
return cache;
}
const commands = await User.findOne({ username: user }, "commands");
await addToCache(user, JSON.stringify(commands));
return commands;
} catch(error) {
console.log(error)
}
};
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