TypeScript：获取Class的非继承属性

Question

class A {
    baseField: number;
}

class B extends A {
    nonInherited: number;
}

type onlyNonInherited = PickNonInherited<B>;

I need my onlyNonInherited type to be equal to the following:

interface NonInherited {
    nonInherited: number;
}

What should be the definition of PickNonInherited ? I've tried to read many posts, but found no solution:(

Answer 1

It's not possible to do this by only looking at the type B . You can however do something like

type OnlyNonInherited = Omit<B, keyof A>;