从 html 表中选择数据并发送到数据库

Question

I am new in using php and html. I have no idea to solve this issue.I am trying to select fetching data from database and display it in html tables and after every row there is button to appoint. if i click that button the data in the row should be saved so i can use it to insert it on other table. [In the select column i want to add a buttton after clicking the button the data in the row should be saved so i can use it later 1

This is code for fetching data and displaying it in table.

 <table style="background-color: white" id="myTable"> <tr> <th> <h1> Email </h1> </th> <th> <h1> Password </h1> </th> <th> <h1> Select </h1> </th> </tr> <?php include 'db_connnection.php'; $conn = OpenCon(); $sql1= "SELECT Email,Password from doctor_information "; $result=mysqli_query($conn,$sql1); $count=mysqli_num_rows($result); if($count < 0) { echo "No Records Available"; } else{ $array1=array(); $count1=0; while ( $row = mysqli_fetch_array($result)) { echo "<tr><td>".$row['Email']."<td>".$row['Password']."<td>"; ?> <?php } }?> </table>

It is not necessary to use a table if there is any other way to solve guide me. Any help will be appreciated.

Answer 1

have an anchor tag like this:-

    <?php

 include 'db_connnection.php';
   $conn = OpenCon();

$sql1= "SELECT * from doctor_information";
$result=mysqli_query($conn,$sql1);
$count=mysqli_num_rows($result);
   if($count < 0) {
            echo "No Records Available";
        }
        else{
         $array1=array();
         $count1=0;
    while($row=mysqli_fetch_array($result))  {  ?>      
    <tr>
         <td> <?php echo $row['Email'];?>  </td>
         <td> <?php echo $row['Password'];?>   </td>
         <td><a href=insert.php?id="<?php echo $row['Email'];?>">INSERT DATA</a></td>    </tr>
<?php } }  ?>

then maybe in your insert.php

<?php
    if(isset($_GET['id']) {
        $Email = $_GET['id'];
        /* your code here to get Email from database, 
        and then insert code with that email
    }
?>