为什么我在 Apple Silicon 上编译的本机应用程序有时构建为 arm64，有时构建为 x86_64？

Question

I have a basic C program:

#include <stdio.h>

int main() {
  printf("Hello, world!\n");
}

When I compile this directly using cc on an Apple Silicon device, it produces an arm64 executable:

% cc hello.c -o hello

% file hello
hello: Mach-O 64-bit executable arm64

% ./hello
Hello, world!

However, when I build it through a build system such as CMake or Ninja, it produces an x86_64 binary:

% ./my-build-system

% file hello
hello: Mach-O 64-bit executable x86_64

I've verified that the command that the build script is running is identical to the one that I run myself. If I copy and paste the command and run it myself, the produced executable is again arm64.

Answer 1

When your build command doesn't include specific flags for which architecture to build for, the compiler tools provided by Apple, like cc , perform some kind of introspection based on the architecture of the calling process . That means that if your build system has yet to be natively compiled for arm64 , you might see this behavior as the compiler will assume you want to build for x86_64!

You can demonstrate this by using the arch tool to run the cc executable in x86_64 mode:

% arch -x86_64 cc hello.c -o hello

% file hello
hello: Mach-O 64-bit executable x86_64

As a work-around, you can introduce a shim compiler that always resets to the native architecture. Save this as force-arm64-cc and make it executable:

#!/usr/bin/env bash

# Note we are using arm64e because `cc` does not have an arm64 binary!
exec arch -arm64e cc "$@"

You can then use this shim in place of cc :

% CC=$PWD/force-arm64-cc ./my-build-system

% file hello
hello: Mach-O 64-bit executable arm64

---

The correct long term solution is to specify the target architecture when compiling:

% arch -x86_64 cc -arch arm64 hello.c -o hello

% file hello
hello: Mach-O 64-bit executable arm64

However, this currently produces a bogus executable when you rebuild the binary, which is quite common in an edit-compile-run cycle:

% ./hello
zsh: killed     ./hello

See also:

• Why does my native arm64 application built using an x86_64 build system fail to be code signed unless I remove the previous executable?