如果在使用 Python 的熊猫中匹配字符串（REGEX）中的条件

Question

I just want to add a if condition before a regex matching: first I define the regex and store the values in Name, then I print the Name value. The result is True and False(Boolean).

Name = df['Name'].str.match('^(\w+\s*)$')
#If the result matches True value passed and else the value will be False
print(Name) 

Result

:
True
False
True

The below code is about the if condition I have. I don't know how to match if condition with a regex. It seems the value of Name which is True/ False hasn't been checked in the if condition.

if Name is True:
     print(Name)
else:
     print('bye')

Code Result:

bye

Expected Result:

John
Saher

Thanks

Answer 1

You can use

df.loc[df['Name'].str.match(r'^\w+\s*$')]

Note you do not need the capturing group with a regex passed as an argument to Series.str.match , it is only required in extract / extractall .

If you want to allow any amount of leading whitespace chars, you may also add \\s* after ^ and use r'^\\s*\\w+\\s*$' .

Pandas test:

import pandas as pd
df = pd.DataFrame({'Name': ['John', '---', 'Saher']})
>>> df.loc[df['Name'].str.match('^(\w+\s*)$')]
    Name
0   John
2  Saher