[英]How to read from std::cin to istringstream
I would like to parse date in format [mm/dd/yy]:我想以 [mm/dd/yy] 格式解析日期:
#include <sstream>
#include <iomanip>
#include <iostream>
#include <time.h>
int main()
{
struct tm time;
std::istringstream ss;
std::cout << "enter string [mm/dd/yy/]: ";
std::cin >> ss;
ss >> std::get_time(&time, "%D");
std::cout << time.tm_wday << std::endl;
}
But I cannot read from std::cin
to std::istringstream
, but why?但我无法从std::cin
读取到std::istringstream
,但为什么呢?
streambuf
.在那里我有 2 个缓冲区(cin -> istream 和 istringstream),它们提供不同的缓冲区(一个用于“字符串”,另一个用于“屏幕 - stdout”),但是为什么当它们仍然只是一个流streambuf
。 How is even the streambuf
implemented in C++?甚至streambuf
是如何用C++实现的? Is it an array?是数组吗? a struct?, Could I find the source implementation of it somewhere?一个结构?,我可以在某处找到它的源实现吗?You could use std::string
and std::getline
:您可以使用std::string
和std::getline
:
std::string input_text;
std::getline(std::cin, input_text);
std::istringstream input_text_stream(input_text);
No need of intermediate std::istringstream
, you might do directly:不需要中间std::istringstream
,你可以直接做:
std::cin >> std::get_time(&time, "%D");
To substitute underlying buffer, you have to call rdbuf
:要替换底层缓冲区,您必须调用rdbuf
:
std::istringstream ss;
std::cout << "enter string [mm/dd/yy/]: ";
ss.basic_ios::rdbuf(std::cin.rdbuf()); // substitute internal ss buffer with std::cin one
ss >> std::get_time(&time, "%D");
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