如何组合两个布尔 lambda 函数来创建一个新的布尔 lambda 函数？

Question

I encountered another problem while making this "infinite"

class Infset:
    def __init__(self, f):
        self.f = f
        
    def __or__(self, other):
        return Infset(self.f or other.f)

    def __and__(self, other):
        return Infset(self.f and other.f)

So far the class function takes in a boolean lambda function as an object. and I have to make methods that will give the union, intersection, and subtraction.

I realized that to do these methods I just have to adjust the limiting boolean functions for example:

A = Infset(lambda x: x%2==0)
B = Infset(lambda x: x%2==1)

But if I were to try or by:

c = A|B

it just checks for the first boolean function and not the second one. Am I doing something wrong here? I also tried this approach:

D = (lambda x: x%2==0) or (lambda x: x%2==1) #which doesn't work. Probably why my code doesn't work
E = lambda x: x%2==0 or x%2==1 #which works

How am I supposed to connect this to my code? Can someone point out my mistake?

Answer 1

Use another lambda for the results. I think you want this:

class Infset:
    def __init__(self, f):
        self.f = f
        
    def __or__(self, other):
        return Infset(lambda x: self.f(x) or other.f(x))

    def __and__(self, other):
        return Infset(lambda x: self.f(x) and other.f(x))

    def __call__(self, x):
        return self.f(x)

A = Infset(lambda x: x%2==0)
B = Infset(lambda x: x%2==1)

C = A | B

for i in range(10):
    print(f'A({i})={A(i)!s:5} B({i})={B(i)!s:5} C({i})={C(i)!s:5}')

A(0)=True  B(0)=False C(0)=True 
A(1)=False B(1)=True  C(1)=True 
A(2)=True  B(2)=False C(2)=True 
A(3)=False B(3)=True  C(3)=True 
A(4)=True  B(4)=False C(4)=True 
A(5)=False B(5)=True  C(5)=True 
A(6)=True  B(6)=False C(6)=True 
A(7)=False B(7)=True  C(7)=True 
A(8)=True  B(8)=False C(8)=True 
A(9)=False B(9)=True  C(9)=True