从嵌套列表 [[name1,score],[name2,score],...] 中，如何删除分数最低的名称？

Question

I have a mixed nested list [[name1,score],[name2,score],...] . How do I remove the names with the lowest score? I selected an element with the lowest score and looped through the list and compared scores and remove if the score matches the min.

lmin=min(list, key = lambda x: x[1])
for l in list:
    if( ls[1] == lmin1[1]):
        ls1.remove(l)

But it doesn't remove all, only the first instance. Where am I making a mistake? Best,

Answer 1

This is a better way to filter:

lmin=min(list_, key = lambda x: x[1])
li = [ item for item in list_ if item[1] != lmin]

Note that you shouldnt use the word list as variable as it is a saved keyword...

Answer 2

You can do it with:

Mylist = [["name1",10],["name2",4],["name3",40]]
print(Mylist)
to_remove=min(Mylist, key = lambda x: x[1])
Mylist.remove(to_remove)
print(Mylist)

result:

[['name1', 10], ['name2', 4], ['name3', 40]]
[['name1', 10], ['name3', 40]]