echo 覆盖 bash 脚本中的行首

Question

I'm trying to formulate curl requests (echo just for a check) based on variables I got from another curl query

My first curl query result assigned to $invno_list variable is

,result,table,invno,latitude,longitude
,_result,0,16734,44.6707726,15.2820759
,_result,0,16768,44.7376213,15.2164268
,_result,0,18061,44.6654625,14.6602612

my script is here

declare -i line_number=0
for inv_line in $(echo "$invno_list" | awk -F'\\\\r\\\\n' '{print}');do
    line_size=${#inv_line} 
    if [ ! $line_number -eq 0 ] && [ $line_size -gt 1 ] #avoiding header line and empty line (last)
    then
    invno=$(echo "$inv_line" | awk 'BEGIN{FS=","}{print $4}')
    lat=$(echo "$inv_line" | awk 'BEGIN{FS=","}{print $5}')
    lon=$(echo "$inv_line" | awk 'BEGIN{FS=","}{print $6}')
    echo "invno is ${invno} lat is ${lat} and lon is ${lon}" #checking variables
    echo "curl -X GET -k -i \"${ownURL}?lat=$lat&lon=${lon}&units=metric\""
fi    
    line_number=$line_number+1
done

The result of this run is

invno is 16734 lat is 44.6707726 and lon is 15.2820759
&units=metric" -i "https://api.openweathermap.org/data/2.5/onecall?lat=44.6707726&lon=15.2820759
invno is 16768 lat is 44.7376213 and lon is 15.2164268
&units=metric" -i "https://api.openweathermap.org/data/2.5/onecall?lat=44.7376213&lon=15.2164268
invno is 18061 lat is 44.6654625 and lon is 14.6602612
&units=metric" -i "https://api.openweathermap.org/data/2.5/onecall?lat=44.6654625&lon=14.6602612

I would expect results to be following type

invno is 40336 lat is 44.6777115 and lon is 15.2872734
curl -X GET -k -i "https://api.openweathermap.org/data/2.5/onecall?lat=44.6777115&lon=15.2872734&units=metric"

Can someone please suggest me what is wrong

Answer 1

Look like Shawn was right there were \\r sign who messed up everything

This line fixed that

$(echo "$invno_list" | awk '{sub(/\r/,"",$NF); print}