使用 jQuery 选择 php 包含的 html 元素
[英]Select php included html element with jQuery
问题描述
I'd like to select an included html element with jQuery.
我想用 jQuery 选择一个包含的 html 元素。 How can I achive this?我怎样才能做到这一点？
index.php索引.php
<?php
<html>
<head>
...
</head>
<body>
include('file.php');
</body>
<html>
?>
file.php文件.php
<?php
echo '<div class="test">test</div>';
?>
select.js选择.js
let a = $('.test');
console.log(a); // returns undefined
2 个解决方案
解决方案1
0 2020-11-19 14:56:35
Try executing your script after the page has fully loaded.在页面完全加载后尝试执行您的脚本。
$(window).on("load", function() {
let test = $('.test');
console.log(test);
});
解决方案2
0 2020-11-19 15:02:56
Code should be organized as follows: <?php Php.Code.Goes.Here ?> .代码应组织如下： <?php Php.Code.Goes.Here ?> 。 This can be surrounded by HTML, for instance, <b><?php print("HELLO!"); ?></b>这可以用 HTML 包围，例如<b><?php print("HELLO!"); ?></b> <b><?php print("HELLO!"); ?></b> . <b><?php print("HELLO!"); ?></b> . This will display: HELLO!这将显示：你好！
So...you see the problem then, with...所以......你看到了问题，然后......
<?php
<html>
<head>
...
</head>
<body>
include('file.php');
</body>
<html>
?>
The HTML is IN the PHP.该HTML在PHP。 You want this:你要这个：
<html>
<head>
...
</head>
<body>
<?php include('file.php'); ?>
</body>
<html>
This code, of course, shouldn't have executed at all, since <?php <html> isn't really valid PHP syntax.当然，这段代码根本不应该执行，因为<?php <html>并不是真正有效的 PHP 语法。
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