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将 yyyyyMMddHHmmssffff 字符串转换为 DateTime.Parse 可接受值的优雅方法?

[英]Elegant way to convert yyyyyMMddHHmmssffff string into acceptable value for DateTime.Parse?

I have "202006260718083370" as an input value and I need to convert it into parse -able string for DateTime.Parse.我有“202006260718083370”作为输入值,我需要将其转换成DateTime.Parse解析-able字符串。 Any elegant way that you can think of aside from the approach below?除了下面的方法,你还能想到什么优雅的方法?

Approach 1 - Individually insert string in between.方法 1 - 在中间单独插入字符串。

var input = "202006260718083370".Insert(5, "-")
                                .Insert(8, "-")
                                .Insert(11, " ")
                                .Insert(14, ":")
                                .Insert(17, ":")
                                .Insert(20, ".");

var dateTime  = DateTime.Parse("2020-06-26 07:18:08.3370") // What input looks like

Approach 2 - individually pass in new DateTime(....)方法 2 - 单独传入 new DateTime(....)

var year = "202006260718083370".Substring(0, 4);
var month = "202006260718083370".Substring(4, 2);
var date = "202006260718083370".Substring(6, 2);
var hour = "202006260718083370".Substring(8, 2);
var min = "202006260718083370".Substring(10, 2);
var sec = "202006260718083370".Substring(12, 2);
var mil = "202006260718083370".Substring(14, 4);

Approach 3 - almost the same in approach 2. Use string array and concat.方法 3 - 与方法 2 几乎相同。使用字符串数组和连接。 Like the answer here .喜欢这里的答案。

Use DateTime.ParseExact with your formatDateTime.ParseExact与您的格式一起使用

From documentation:从文档:

Converts the specified string representation of a date and time to its DateTime equivalent.将日期和时间的指定字符串表示形式转换为其等效的 DateTime。 The format of the string representation must match a specified format exactly or an exception is thrown.字符串表示的格式必须与指定的格式完全匹配,否则会引发异常。

var provider = CultureInfo.InvariantCulture;
var parsedDateTime = DateTime.ParseExact("202006260718083370", "yyyyMMddHHmmssffff", provider);

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