如何通过条件使用“with”laravel 关系函数来获取数据？

Question

this is my table => table image

//This is my controller
public function listUserStripeActionableRequests(Request $request) {
        return $model = UserRequest::whereNull('deleted_at')
            ->with('oldPackage')
            ->get();
}


userRequest.php

public function oldPackage() {
    return $this->hasOne(Package::class, 'id', 'old_package_id');
}

I need to get data according to package_type in the table if package_type == 1 then i need to get data from Package::class, if package_type == 2 then from AddOnsPackage::class then model function like :- $this->hasOne(AddOnsPackage::class, 'id', 'old_package_id');

How can i use single query to get data accordingly?

Answer 1

You can try

class UserRequest extends Model
{


    public function package()
    {
        return $this->hasOne(Package::class, 'id', 'old_package_id');
    }

    public function addon()
    {
        return $this->hasOne(AddonPackage::class, 'type', 'add_on_type');
    }

    public static function sorted()
    {
        return static::whereNull('deleted_at')
            ->get()
            ->map(function ($record) {
                if ($record->package_type === 1) {
                    $record->load('package');
                } elseif ($record->package_type === 2) {
                    $record->load('addon');
                }

                return $record;
            });
    }
}

Then in the controller you can do

public function listUserStripeActionableRequests(Request $request)
{
    return $model = UserRequest::sorted();
}