[英]Sorting singly linked list using insertion sort in python
I'm new to python coming form c++ i don't know how to work with linked list without pointers, that being said I've written this code but it returns the same list without sorting it at all我是来自 c++ 的 python 新手,我不知道如何在没有指针的情况下使用链表,据说我已经编写了这段代码,但它返回了相同的列表,根本没有对其进行排序
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
def insertionSortList(head):
if head.next==None:
return head
#checkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkks
loop=head
i=head
while(i.next!=None):
save_val=i.next
i=i.next.next
while True:
if loop!=i and save_val.val>loop.val:
loop=loop.next
else:
if loop==head:
save_val=loop
break
else:
save_val=loop.next
loop=save_val
loop=head
break
return head
You are not incrementing the loop node variable.您没有增加循环节点变量。 Your code breaks out of the inner while loop before the loop node variable gets a chance to increment
loop=loop.next
.您的代码在循环节点变量有机会增加
loop=loop.next
之前跳出内部 while 循环。 Here is my solution, I separated the Node and Linked List classes.这是我的解决方案,我将 Node 和 Linked List 类分开。 Setup a length variable and incremented the value each time I inserted a node.
每次插入节点时,设置一个长度变量并增加该值。 Then used the normal insertion sort method.
然后使用正常的插入排序方法。
class Node:
def __init__(self,value):
self.value = value
self.next = None
class ListNode:
def __init__(self):
self.head = None
self.length = 0
def __repr__(self):
'''Allows user to print values in the ListNode'''
values = []
current = self.head
while current:
values.append(current.value)
current = current.next
return ', '.join(str(value) for value in values)
def insert(self,value):
'''Inserts nodes into the ListNode class'''
newNode = Node(value)
if self.head is None:
self.head = newNode
else:
newNode.next = self.head
self.head = newNode
self.length += 1
return self
def insertionSortList(self):
'''Insertion sort method: held a temp variable and inserted the smallest value from temp through the rest of the list then incremented temp variable to the next idx/node'''
current = self.head
for _ in range(self.length-1):
tempNode = current.next
while tempNode:
if tempNode.value < current.value:
current.value, tempNode.value = tempNode.value, current.value
tempNode = tempNode.next
current = current.next
return self
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