如何在for循环中打印整数？

Question

In Python, how do I print integer one below the other:

a1 = "Great"
a2 = 100
for all in a1:
    print(all)

Output:

G
r
e
a
t

Question: How do I write for / print statement for the variable a2 , so that my output will be:

1
0
0

?

Answer 1

An object of type int is not iterable. So force it to be iterable by making it a string .

x = 1337
for num in str(x):
  print(num)

Answer 2

You need to convert a2 , an int into something that is iterable. One way you could do this is by converting a2 into a string:

a2 = 100
for str_digit in str(a2): # if a2 is negative use str(a2)[1:] to not print '-' sign
    print(str_digit)

And another way could be by extracting the individual digits (still as ints) from a2 into a list (or another iterable):

def get_digits(num):
    num = abs(num)
    digits = []
    while num != 0:
        digits.append(num % 10)
        num //= 10
    return digits

a2 = 100
for str_digit in get_digits(a2):
    print(str_digit)

Output:

1
0
0

Answer 3

To get letters of a word or elements of a number by a for loop you need a string

a = 100 is an integer so you need to convert it to a string like below :

a=str(100)
for i in a:
    print(i)