如何检索特定字符串之前的最后一个字符数组

Question

row1: 10016/Documents/folder1/abc.pdf

row2: 10016-10017/10017/Documents/folder1/folder2/xyz.pdf

I'm trying to retrieve the string before /Documents but if there is any / before, I need to retrieve the string after that

In row 1, I need to retrieve 10016

In row 2, I need to retrieve 10017

I tried

var output = filepath.split("/").slice(0,1);

Answer 1

You can split by '/Documents/', try this:

 let str = '10016/Documents/abc.pdf'; console.log(str.split('/Documents/')[0])

Answer 2

Split by /Documents/ then split that by / and get the final element:

 const row1 = "10016/Documents/folder1/abc.pdf"; const row2 = "10016-10017/10017/Documents/folder1/folder2/xyz.pdf"; let docs = row1.split("/Documents/")[0]; let nums = docs.split("/"); nums = nums[nums.length - 1]; console.log(nums); docs = row2.split("/Documents/")[0]; nums = docs.split("/"); nums = nums[nums.length - 1]; console.log(nums);

This works for both row1 and row2 as you can see.

Answer 3

You can use regular expression to get this

([a-z\d]+)\/Documents

Explaining the regular expression

• Capture everything which contains one or more occurrences ( + ) occurrence of either an alphabet (az) or digit (/d)
• Also make sure this set of characters are right before a /Documents phrase

 let result = RegExp(/([az\\d]+)\\/Documents/).exec('10016/Documents/abc.pdf'); if (result) { console.log(result[1]) } result = RegExp(/([az\\d]+)\\/Documents/).exec('10016-10017/10017/Documents/xyz.pdf'); if (result) { console.log(result[1]) }