TypeError：'int'对象在python3.8中不可下标

Question

Alphabet = ["a","b","c","ç","d","e","f","g","ğ","h","ı","i","j","k","l","m","n","o","ö","p","r","s","ş","t","u","ü","v","y","z"]

message = 'cöimamiçknsyznhaczstş'
for i in range(len(message)):
    message = Alphabet.index(message[i])

I m trying to write simple code but I keep getting this TypeError: 'int' object is not subscriptable error

I just want to get index of each char of message

Answer 1

You are doing everything correctly, just a little change is needed because in your code you are overwriting our message variable. here is how you can fix it

 Alphabet = ["a","b","c","ç","d","e","f","g","ğ","h","ı","i","j","k","l","m","n","o","ö","p","r","s","ş","t","u","ü","v","y","z"] message = 'cöimamiçknsyznhaczstş' char_indexes = [] for i in range(len(message)): char_indexes.append(Alphabet.index(message[i])) print(char_indexes)

Another method to do the same is to useList comprehension as follows.

 Alphabet = ["a","b","c","ç","d","e","f","g","ğ","h","ı","i","j","k","l","m","n","o","ö","p","r","s","ş","t","u","ü","v","y","z"] message = 'cöimamiçknsyznhaczstş' char_indexes = [Alphabet.index(message[i]) for i in range(len(message))] print(char_indexes)

Answer 2

You are overwriting message and it becomes integer after first iteration. Try this:

Alphabet = ["a","b","c","ç","d","e","f","g","ğ","h","ı","i","j","k","l","m","n","o","ö","p","r","s","ş","t","u","ü","v","y","z"]

placeholder_list = []
message = "cöimamiçknsyznhaczstş"
for i in range(len(message)):
    placeholder_list.append(Alphabet.index(message[i]))
print(placeholder_list)

Answer 3

After the first iteration, you assign to message the index of the first location of the first letter of the original message which is 2. In the next iteration, message=2 and you try to do message[1] but message is not an integer and therefore it is not subscriptable.

The solution is probably to change the loop to something like -

for i in range(len(message)):
    x = Alphabet.index(message[i])