如何获得我在 function 范围内声明的数组的总和？

Question

I've made the range function which gives me the integers between start and end . Now i have to make a sum function, that takes range as a parameter and gives the sum of that.

function range(start, end) {

    let numbers = [];

    for(i=start; i <= end; i++) {

        numbers.push(i);

    }
    return numbers;
}
console.log(range(1,5));

function sum(arrayOfNumbers) {

    var sumOfNo;

    for(i=0; i <= arrayOfNumbers; i++) {
        
        arrayOfNumbers += sumOfNo;
    }

    return sumOfNo;
}
console.log(sum(range(10,15)));

Answer 1

you can use reduce for this

 function range(start, end) { let numbers = []; for (i = start; i <= end; i++) { numbers.push(i); } return numbers; } console.log(range(10, 15)); function sum(arrayOfNumbers) { return arrayOfNumbers.reduce((a, n) => { return a += n; }, 0) } console.log(sum(range(2, 4)));

Answer 2

Some errors I find from the code (in sum function)

• for loop need to loop less than arrayOfNumbers.length not arrayOfNumbers
• values need to be added to the sumOfNo not the other way around.

the following resolves it.

 function range(start, end) { let numbers = []; for(i=start; i <= end; i++) { numbers.push(i); } return numbers; } console.log(range(1,5)); function sum(arrayOfNumbers) { var sumOfNo = 0; for(i=0; i < arrayOfNumbers.length; i++) { sumOfNo += arrayOfNumbers[i]; } return sumOfNo; } console.log(sum(range(10,15)));

Answer 3

 function getSumFromRange(start, end) { return ((end * (end + 1)) / 2) - ((start * (start + 1)) / 2) + start; } console.log(getSumFromRange(1, 10));

JSFiddle: click here

it will be the efficient way to find sum of range. using simple liner female, referThe nth partial sum of the series