如何根据 Folder2 文件名重命名 Folder1 中的文件？

Question

I have 1000+ files in 2 folders(same amount).

EXAMPLE

Folder1/
   0.json
   1.json
   2.json

Folder2/
   some_name1.xml
   some_name2.xml
   some_name3.xml

I want to rename all files in 1st folder based on second folder file names BUT NOT THE EXTENSIONS

I got this script. It must just rename all files one by one But now it got a problem, after renaming files there are shuffled which means information are not same as files in folder1. Any ideas how to fix that?

from pathlib import Path

src = Path(r"/home/folder2")
dst = Path(r"/home/folder1")
for s, d in zip(src.iterdir(), dst.iterdir()):
    d.rename(d.with_name(s.with_suffix(d.suffix).name))

Answer 1

The following is an example of a key function that will use the first integer found within a file name as the sort key, otherwise just the file name (all files that do not contain integers within their file names will come last in the sort):

from pathlib import Path
import re
import math

rex = re.compile(r'\d+')
def my_key_function(path):
    m = rex.search(path.name)
    # file names without integers in them will be sorted last:
     return (int(m[0]) if m else math.inf, path.name)

for s, d in zip(sorted(src.iterdir(), key=my_key_function()), sorted(dst.iterdir(), key=my_key_function)):
    etc.