JavaScript - 匹配 0.01 到 99 之间的任何数字的正则表达式

Question

I'm working on a form where there's an "Interest Rate" Field which has accept values between 0.01 and 99.00

I've already looked a RegEx Up from 0.01 to 99.99 in a regular expression . This almost does the trick. The only challenge that I'm getting is to make it to NOT MATCH numbers from 99.01 to 99.99.

I've updated it to cater to up to 10 digits after the decimal point.

Test Data:

Should only match numbers between 0.01 and 99.00

Should Not Match

• 00.00
• 100.134234
• 99.01234 // this is matching, but should not match with my current RegEx.
• 100

Should Match

• 0.01
• 0.10
• 1.233
• 3.20
• 4.655
• 5.112
• 99.00
• 99.0

I've already created a RegEx101 Sandbox which I feel might be useful.

Answer 1

At the beginning, add a negative lookahead for 99 followed by anything but .00 :

(?!99\.0*[^0\n])

https://regex101.com/r/R63oyb/10

excluding 99.01 and 99.10 and so on, but permitting 99.00 and 99 .

Answer 2

Here's my approach:

^(?:(?![0.]+$|99)|(?=(?:99|99\.0+)$))\d{1,2}(?:\.\d+)?$

See the test cases

• \d{1,2}(?:\.\d+)? Matches 1-2 digit numbers optionally followed by a decimal point and some digits
• (?:(?.[0?]+$|99)|(?=(:.99|99\.0+)$))
  • (?.[0.]+$|99) Tests if the number is only formed by 0 and . or starting with 99 , fails it. This eliminates 0 and 99
  • |(?=(?:99|99\.0+)$) Unless the number is pure 99 or 99 followed by a decimal point and a bunch of 0 s, let it pass.